What is the solution to the system of equations below?
y = one-half x + 6 and y = negative three-fourths x minus 4
(–8, 2)
(–8, –1)
(8, 10)
(8, –10)
y = one-half x + 6 and y = negative three-fourths x minus 4
(–8, 2)
(–8, –1)
(8, 10)
(8, –10)
Answer
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Answer:
(-8, 2)
Step-by-step explanation:
1. Set up the equations.
y = 1/2x + 6
y = -3/4x - 4
2. Set the equations to equal each other.
1/2x + 6 = -3/4x - 4
3. Move the variables to one side and the numbers to the opposite side.
6 + 4 = -3/4x - 1/2x
10 = -3/4x - 2/4x
10 = -5/4x
4. Divide 10 by -5/4.
10/ -5/4 = 10 * -4/5 (when dividing fractions, flip the fraction over)
10 * -4/5 = -40/5 = -8
x = -8
5. Plug in the x-value into one of the equations.
y = 1/2x + 6
y = 1/2(-8) + 6
y = -4 + 6
y = 2
OR
y = -3/4x - 4
y = -3/4(-8) - 4
y = 6 - 4
y = 2