If $a = 4$, $b = 2$, and $c = -5$, then what is the value of $\\sqrt[3]{4a^4b^5} + \\dfrac{a - c}{(b+c)^2}$?
Answer is not 13 or 31.
Answer is not 13 or 31.
Answer
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Then the expression evaluates to 32 + 1 = 33.