+10

11 months ago

SAT

High School

Given the values of the capacitance of the capacitor and the potential difference, the amount of charge that is stored is 5 picoCoulombs.

The capacitance of a capacitor is simply the ratio of the maximum charge that can be stored in a capacitor to the applied voltage across its plates.

It is expressed as;

C = Q / V

Where Q is charge and V is potential difference.

Given the data in the question;

To determine the amount of charge stored, we substitute our given values into the expression above.

Q = CV

Q = (2.0 × 10⁻¹² F) × 2.5V

Q = 5 × 10⁻¹²C

Q = 5pC

Therefore, given the values of the capacitance of the capacitor and the potential difference, the amount of charge that is stored is 5 picoCoulombs.

Learn more about capacitance here: https://brainacademy.pro/question/14363316

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Given the values of the capacitance of the capacitor and the potential difference, the

amountofchargethat isstoredis5 picoCoulombs.Capacitance of a CapacitorThe

capacitanceof acapacitoris simply theratioof themaximum chargethat can be stored in acapacitorto theapplied voltageacross its plates.It is expressed as;

C = Q / VWhere Q is charge and V is potential difference.

Given the data in the question;

To determine the amount of

charge stored, we substitute our given values into the expression above.C = Q / V

Q = CV

Q = (2.0 × 10⁻¹² F) × 2.5V

Q = 5 × 10⁻¹²C

Q = 5pCTherefore, given the values of the capacitance of the capacitor and the potential difference, the

amountofchargethat isstoredis5 picoCoulombs.Learn more about

capacitancehere: https://brainacademy.pro/question/14363316