A capacitor has a capacitance of 2.00 pf. how much charge is stored when the potential difference is 2.5 v?
0 (0 stars)
0
nuhulawal20 1 year ago
107 response - 0 helps

Given the values of the capacitance of the capacitor and the potential difference, the amount of charge that is stored is 5 picoCoulombs.

### Capacitance of a Capacitor

The capacitance of a capacitor is simply the ratio of the maximum charge that can be stored in a capacitor to the applied voltage across its plates.

It is expressed as;

C = Q / V

Where Q is charge and V is potential difference.

Given the data in the question;

• Capacitance C = 2.00 pF = 2.0 × 10⁻¹² F
• Potential difference V = 2.5V
• Amount of charge stored Q = ?

To determine the amount of charge stored, we substitute our given values into the expression above.

C = Q / V

Q = CV

Q = (2.0 × 10⁻¹² F) × 2.5V

Q = 5 × 10⁻¹²C

Q = 5pC

Therefore, given the values of the capacitance of the capacitor and the potential difference, the amount of charge that is stored is 5 picoCoulombs.