Given the values of the capacitance of the capacitor and the potential difference, the amount of charge that is stored is 5 picoCoulombs.

Capacitance of a Capacitor

The capacitance of a capacitor is simply the ratio of the maximum charge that can be stored in a capacitor to the applied voltage across its plates.

It is expressed as;

C = Q / V

Where Q is charge and V is potential difference.

Given the data in the question;

• Capacitance C = 2.00 pF = 2.0 × 10⁻¹² F

• Potential difference V = 2.5V

• Amount of charge stored Q = ?

To determine the amount of charge stored, we substitute our given values into the expression above.

C = Q / V

Q = CV

Q = (2.0 × 10⁻¹² F) × 2.5V

Q = 5 × 10⁻¹²C

Q = 5pC

Therefore, given the values of the capacitance of the capacitor and the potential difference, the amount of charge that is stored is 5 picoCoulombs.

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