A new car is purchased for $31,000 and over time its value depreciates by one half

every 6.5 years. How long, to the nearest tenth of a year, would it take for the value

of the car to be $3,800?

every 6.5 years. How long, to the nearest tenth of a year, would it take for the value

of the car to be $3,800?

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EThinOh
2 years ago

1 answer - 0 helps
**Answer:**

t≈19.7

**Step-by-step explanation:**

I do not have one, I apologize.

Using an

exponentialfunction, it is found that it would take19.68 yearsfor the value of the car to be $3,800.## What is an exponential function?

A decaying exponential function is

modeledby:In which:

A(0)is the initial value.ris the decay rate, as a decimal, after each n years.In this problem:

A(0) = 31000.r = 0.5, n = 6.5.Then, the

equationis:The value would be of $3,800 at t for which

A(t) = 3800, hence:t = 19.68.

It would take

19.68 yearsfor the value of the car to be $3,800.More can be learned about

exponential functionsat https://brainacademy.pro/question/25537936