10 grams CH10 + excess O2 → ? grams CO2 + H2O
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jsimpson11000 11 months ago
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Answer:

20  gm  CO2

Explanation:

CH10   mole weight = ~ 22 gm

  each 22 gm CH10 produces 44 gm CO2

        44 / 22 = x / 10 = 20 gm

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