+10
1 year ago
Chemistry
College
The volume of the 1.75 M H₃PO₄ solution required to neutralize 50 ml of 3.5 M Ca(OH)₂ solution is 66.67 mL
2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O
From the balanced equation above,
MaVa / MbVb = nA / nB
(1.75 × Va) / (3.5 × 50) = 2/3
(1.75 × Va) / 175= 2/3
Cross multiply
1.75 × 3 × Va = 175 × 2
5.25 × Va = 350
Divide both side by 5.25
Va = 350 / 5.25
Va = 66.67 mL
Thus, the volume of the H₃PO₄ solution needed is 66.67 mL
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https://brainacademy.pro/question/14356286
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The volume of the 1.75 M H₃PO₄ solution required to neutralize 50 ml of 3.5 M Ca(OH)₂ solution is 66.67 mL
Balanced equation
2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O
From the balanced equation above,
How to determine the volume of H₃PO₄
MaVa / MbVb = nA / nB
(1.75 × Va) / (3.5 × 50) = 2/3
(1.75 × Va) / 175= 2/3
Cross multiply
1.75 × 3 × Va = 175 × 2
5.25 × Va = 350
Divide both side by 5.25
Va = 350 / 5.25
Va = 66.67 mL
Thus, the volume of the H₃PO₄ solution needed is 66.67 mL
Learn more about titration:
https://brainacademy.pro/question/14356286